if an electron is revolving in 5d subshell,then what are the possible sets of 4 quantum nos. for the same.Please answer with proper explanation.
if the ans.is:-
n=5
l=2
m=-2,-1,0,1,2
s=-1/2 or 1/2
then what about the formulae which mathematically relates them as:-
l=0 to n-1
m=-l to +l

Asked by mth06111997 | 10th Jun, 2015, 09:04: AM

Expert Answer:

Actual set of quantum number is as given below:

 

    n                l (0 to (n-1))                           m (-l to l)                              Subshell

n = 5         0                                         0                                 5s

                1                                    -1, 0, 1                              5p

                2                               -2, -1, 0, 1, 2                          5d

                3                          -3, -2, -1, 0, 1, 2, 3                       5f

                4                     -4, -3, -2, -1, 0, 1, 2, 3, 4                   5g

 

Formulas for calculation of l and m give idea about the quantum numbers of all subshells.

Therefore,

l = 0 to (n-1) = 0 to (5-1) = 0 to 4

m = - l to l which also shown above.

But we are specifically talking about 5d-orbital because the electron is revolving in 5d-subshell, so the set will be as given below:

n = 5

l = 2

m = -2, -1, 0, +1, +2

s = +1/2 or -1/2

Answered by Arvind Diwale | 10th Jun, 2015, 12:20: PM