CBSE Class 11-science Answered
Actual set of quantum number is as given below:
n l (0 to (n-1)) m (-l to l) Subshell
n = 5 0 0 5s
1 -1, 0, 1 5p
2 -2, -1, 0, 1, 2 5d
3 -3, -2, -1, 0, 1, 2, 3 5f
4 -4, -3, -2, -1, 0, 1, 2, 3, 4 5g
Formulas for calculation of l and m give idea about the quantum numbers of all subshells.
Therefore,
l = 0 to (n-1) = 0 to (5-1) = 0 to 4
m = - l to l which also shown above.
But we are specifically talking about 5d-orbital because the electron is revolving in 5d-subshell, so the set will be as given below:
n = 5
l = 2
m = -2, -1, 0, +1, +2
s = +1/2 or -1/2