If ABC is an equilateral triangle with co-ordinates of B(-3,0) and of C(3,0). Find the co-ordinates of vertex A

Dear Student

Given that  ABC is an equilateral triangle with co-ordinates of B as (-3,0) and of Cas(3,0)

Let Coordinates ofA be (x,y) so AB=BC=AC

AB² =BC² =AC²

using Distance Formula

So(x+3)²+y²=(x-3)²+y²

gives 6x =0 or x =0

Also (x-3)²+y² =36

using x = 0  we get y =3

So required coordinate is (0,3)