If a hall 18m72cm in length & 13m70cm broad is to be paved , find the least no. of tiles of same length that come in it.

Asked by Shreyash Taori | 22nd Apr, 2013, 04:52: AM

Expert Answer:

The question seems incomplete. If the hall is to be paved with square tiles, then the answer is as follows:
 
 
Length = 18 m 72 cm = 1872 cm
Breadth = 13 m 70 cm = 1370 cm
 
Largest size of square tile = HCF of 1872 and 1370
 
Applying Euclid division algorithm,
1872 = 1370 x 1 + 502
1370 = 502 x 2 + 366
502 = 366 x 1 + 136
366 = 136 x 2 + 94
136 = 94 x 1 + 42
94 = 42 x 2 + 10
42 = 10 x 4 + 2
10 = 2 x 5 + 0
 
So, HCF = 2
Therefore, largest size of the square tile = 2 cm
 
Number of tiles required = Area of rectangular hall to be paved / Area of one tile = 1872x1370/2x 2 = 641160

Answered by  | 22nd Apr, 2013, 12:24: PM

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