If a branch of current divides into two branches having same resistance can we say that the current in both branches will be same and half of what was the current in main branch.and will the voltage at the end of both branches be same.
Asked by Prasad.abhinava | 26th Jun, 2014, 08:29: PM
A branch of current divides into two branches having same resistance indicates that its a parallel connection wherein the current divides into two.
If I is the total current flowing in the circuit and I1 and I2 the current flowing through the two individual branch respectively.
i.e I = I 1+I 2
When two resistance are connected in parallel , the amount of current flowing through each branch depends upon the resistance in each branch ( I = V / R ) but the sum of current flowing through each individual parallel branches is equal to the total current flowing in the circuit as a whole.I = I 1+I 2.
And the potential difference across each resistance is the same which is equal to the voltage of the battery applied.
Here as the resistance in both the branch is the same the current I1 = I2 , and I = I 1+ I 2
I = I 1+I 2= 2 I 1
I = 2 I 1
As I is the current in the main branch , current in individual branches I 1 and I 2 = I / 2
The voltage at the ends of both branches will be same and will be equal to the voltage of the battery used.
Answered by Jyothi Nair | 30th Jun, 2014, 09:26: AM
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