CBSE Class 11-science Answered
if a be the smallest positive root of the equation
?sin(1-x) = ?cosx,
then the approximate integral value of (a-1) must be?
Asked by | 13 Nov, 2012, 01:35: PM
Expert Answer
?sin(1-x) = ?cosx
Squaring both side with condition that sin(1-x)>0,cosx>0
Sin (1-x)=cosx
Cosx=cos(?/2-1+x)
x=2n?±(?/2-1+x)nI
Considering only negative sign as +sign will give no solution
x=2n?-?/2+1-x
2x=2n?-?/2+1
For smallest positive root
n=1
2x=2?-?/2+1
x=3?/4+1/2 does not satisfy the condition that sin(1-x)>0,cosx>0
n=2
x=7?/4+1/2satisfy the condition that sin(1-x)>0,cosx>0
so approximate integral value of root=6
so a=6
a-1=5
Answered by | 18 Nov, 2012, 04:43: PM
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