CBSE Class 12-science Answered
if a , b,c are three mutually perpendicular vectors of equal magnitude then prove
Asked by | 20 Feb, 2009, 05:21: PM
Expert Answer
let θ be the angle between a+b+c and a. then
cos θ = (a+b+c).(a) / |a| |a+b+c|
=a.a/ |a| 
3 |a|
=1 / 3
since a ,b c are mutually perpendicular so | a +b+c | will be |a|2 + |b|2 + | c |2 = 3 |a| ( |a| = |b| = |c| )
Answered by | 20 Feb, 2009, 10:56: PM
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