If A, B and C are interior angles of triangle ABC, then show that sin (C+A/2) = cos B/2 by using angle sum property

Asked by Renoy Gladson | 17th May, 2013, 10:06: AM

Expert Answer:

sin [(C+A)/2]
= sin (90 - B/2)    Since, A + B + C = 180
= cos B/2

Answered by  | 17th May, 2013, 10:10: AM

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