CBSE Class 11-science Answered
If a,b and c are in geometric progression and a+b+c=xb,then prove that x3.
Asked by | 05 Jul, 2008, 03:41: PM
Expert Answer
As a,b,c are in geometric progression,
let b=ar and c=ar2
Now ,a(1+r+r2)=xar
Hence x=1+r+1/r
Now by AM >= GM
(r+1/r)/2 >= (r*1/r)1/2 for r>=0
and (r+1/r)/2 <= (r*1/r)1/2 for r>=0
Hence,
r+1/r >=2 or r+1/r <=-2,Depending on whether r >0 or r<0.
Hence x>3 or x<-1
Answered by | 18 Jul, 2008, 09:54: AM
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