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CBSE Class 11-science Answered

<div>If 8.3 ml of a sample of H2SO4(36N) is diluted by 991.7 ml of water, the approximate normality of resulting solution is</div>
Asked by Anil | 16 May, 2017, 10:21: PM
Expert Answer

V1N1= V2N2
V2 = 8.3 + 991.7
Substituting the values,
8.3 x 36 = 1000 x N2
N2= 8.3 x 36/ 1000
      = 0.2988N

Answered by Vaibhav Chavan | 17 May, 2017, 11:37: AM

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