If 8.3 ml of a sample of H2SO4(36N) is diluted by 991.7 ml of water, the approximate normality of resulting solution is

Asked by Anil | 16th May, 2017, 10:21: PM

Expert Answer:

V1N1= V2N2
V2 = 8.3 + 991.7
Substituting the values,
8.3 x 36 = 1000 x N2
N2= 8.3 x 36/ 1000
      = 0.2988N

Answered by Vaibhav Chavan | 17th May, 2017, 11:37: AM