IF 3g OF HYDROGEN IS MIXED WITH 8g OF OXYGEN AND THE MIXTURE IS IGNITED, ?CONTD.................
Asked by KEERTHIKAY | 27th Nov, 2008, 06:31: AM
Expert Answer:
2H2 + O2 =2 H2O
4g of H2 = 32 g of O2
3g of H2 = 3x32/4 g of O2
=24g of O2 required but we have only 8 g so it is limiting reagent.
32g of O2 gives = 36 g H2O
8 g of O2 gives = 36 x8 /32g H2O
=9g of H2O
Answered by | 27th Nov, 2008, 11:08: AM
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