IF 3g OF HYDROGEN IS MIXED WITH 8g OF OXYGEN AND THE MIXTURE IS IGNITED, ?CONTD.................

Asked by KEERTHIKAY | 27th Nov, 2008, 06:31: AM

Expert Answer:

2H2 + O2 =2 H2O

4g of H= 32 g of O2

3g of H= 3x32/4 g of O2

                 =24g of O2 required but we have only 8 g so it is limiting reagent.

32g of O2 gives = 36 g H2O

8 g of O2 gives = 36 x8 /32g H2O

                            =9g of H2O

Answered by  | 27th Nov, 2008, 11:08: AM

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