CBSE Class 10 Answered
If 1/a,1/b,1/c are in a.p show that a(b+c),b(c+a),c (a+b) are in a.p
Asked by | 27 Oct, 2012, 09:01: AM
Expert Answer
Answer : Given :If 1/a,1/b,1/c are in a.p
To prove : a(b+c),b(c+a),c (a+b) are also in a.p
1/a, 1/b, 1/c are in AP
=> (1/a) + (1/c) = 2(1/b) {x, y, z are in AP iff : x + z = 2y}
=> (c+a) / (ca) = 2/b
=> b(c+a) = 2(ca)
(bc+ab) = 2(ca) ................... (1)
1/a, 1/b, 1/c are in AP
=> (1/a) + (1/c) = 2(1/b) {x, y, z are in AP iff : x + z = 2y}
=> (c+a) / (ca) = 2/b
=> b(c+a) = 2(ca)
(bc+ab) = 2(ca) ................... (1)
now , a(b+c) + c(a+b)
= ab + ca + ca + bc
= (bc+ab) + 2(ca)
= (bc+ab) + (bc+ab) ............ from (1)
= 2(bc+ab)
=> a(b+c) + c(a+b) = 2 b(c+a) {x, y, z are in AP iff : x + z = 2y}
= ab + ca + ca + bc
= (bc+ab) + 2(ca)
= (bc+ab) + (bc+ab) ............ from (1)
= 2(bc+ab)
=> a(b+c) + c(a+b) = 2 b(c+a) {x, y, z are in AP iff : x + z = 2y}
a(b+c),b(c+a),c (a+b) are in a.p
Hence Proved
Answered by | 27 Oct, 2012, 07:38: PM
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