If 0.5 mole of BaCl2 is mixed with 0.2 mole of Na3PO4, the maximum no. of mole of NaCl that can be formed is

Asked by Anil | 17th May, 2017, 02:31: PM

Expert Answer:

Balanced equation for reaction between BaCl2 and Na3PO4 is as follows:

3BaCl2 + 2Na3PO4 → Ba3(PO4)2  + 6NaCl

3 moles of BaCl2 react with 2 moles of Na3PO4 to give 1 mole of Ba3(PO4)2

0.5 moles of BaCl2 will react with (2/3) x 0.5 = 0.33 moles of Na3PO4

Available moles of Na3PO4 = 0.2

So, Na3PO4 is the limiting reagent

Now, 2 moles of Na3PO4 give 1 mole of Ba3(PO4)2

So, 0.2 moles of Na3PO4 will give ½ x 0.2 = 0.1 mole of Ba3(PO4)2

Hence, maximum number of moles of Ba3(PO4)2 formed = 0.1

Answered by Prachi Sawant | 17th May, 2017, 03:27: PM