I want the solution to the physics numerical qestion?

For car A , u = 52km/hr = 14.4m/s

For car B , u = 3km/hr = 0.83m/s

now distance travelled by car A = speed x time taken to stop car A

                                                        = 14.4 m/s x 5sec

                                                        = 72m.

now distance travelled by car A = speed x time taken to stop car B

                                                        = 0.83m/s x 10sec

                                                        = 8.3 m.

So car A travelled farther after brakes were applied.

regards

toppers expert