I want the solution to the physics numerical qestion?

Asked by avi123 | 3rd May, 2008, 12:07: PM

Expert Answer:

For car A , u = 52km/hr = 14.4m/s

For car B , u = 3km/hr = 0.83m/s

now distance travelled by car A = speed x time taken to stop car A

                                                        = 14.4 m/s x 5sec

                                                        = 72m.

now distance travelled by car A = speed x time taken to stop car B

                                                        = 0.83m/s x 10sec

                                                        = 8.3 m.

So car A travelled farther after brakes were applied.

regards

toppers expert

Answered by  | 26th May, 2008, 02:52: AM

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