I want the solution to the physics numerical qestion?
Asked by avi123 | 3rd May, 2008, 12:07: PM
For car A , u = 52km/hr = 14.4m/s
For car B , u = 3km/hr = 0.83m/s
now distance travelled by car A = speed x time taken to stop car A
= 14.4 m/s x 5sec
now distance travelled by car A = speed x time taken to stop car B
= 0.83m/s x 10sec
= 8.3 m.
So car A travelled farther after brakes were applied.
Answered by | 26th May, 2008, 02:52: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number