I require help with this sum: Prove that: 1/tan3A-tanA -1/cot3A-cotA=cot2A
Asked by | 30th Jul, 2012, 11:46: AM
Expert Answer:
(1 / {tan 3A - tan A}) =(cot 3A cot A)/(cot A - Cot 3A)
1/(cot 3A - cot A) = - 1/(cot A - cot 3A)
On subtracting, we get,
(1 + cot 3A cot A)/(cot A - cot 3A) = cot (3A - A) = cot2A
(1 / {tan 3A - tan A}) =(cot 3A cot A)/(cot A - Cot 3A)
1/(cot 3A - cot A) = - 1/(cot A - cot 3A)
On subtracting, we get,
(1 + cot 3A cot A)/(cot A - cot 3A) = cot (3A - A) = cot2A
(1 + cot 3A cot A)/(cot A - cot 3A) = cot (3A - A) = cot2A
Answered by | 30th Jul, 2012, 01:53: PM
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