i^i???

Asked by mayur_hampi | 30th Nov, 2009, 08:52: PM

Expert Answer:

ii = eilog i,

We can write i log i = i log eπi/2 = i (πi/2) = -π/2.

Hence,

ii = eilog i = e -π/2

Regards,

Team,

TopperLearning.

Answered by  | 1st Dec, 2009, 11:58: AM

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