I have written the correct question.This is from S chand sample papers. Is there any other way to prove m=l, so that we can prove mx=ly If the distance of P(x,y) from A(l+m, l-m) and B (l-m, l+m) are equal, prove that mx=ly

Hi Divya,

 

We have checked our solution. It seems fine. 

We have also understood how to obtain mx=ly.

You need to change the x-coordinate of the point B, which should be m-l and NOT l-m.

For this problem, you will surely get x = y only.

You can refer to the following link for this question too. It has appeared in CBSE 2016 board paper.

The solution is there too, and you will see that ,

the point B, which should be m-l and NOT l-m.

 

http://www.topperlearning.com/study/cbse/class-10/mathematics/previous-year-question-papers/b101c2s3e8

 

It is similar to Question Number 13.

If the point P(x, y) is equidistant from the points A(a + b, b – a) and B(a – b, a + b). Prove that bx = ay.

Only in place of a they took m and in place of b they took l.