I have a question in construction??
Asked by | 9th Oct, 2008, 08:22: PM
1.Draw the triangle ABC
2.Draw aray BX making an acute angle with BC on the other side of the triangle.
3.Locate 4 points on the arm BX (the larger out of 4 and 3) , with your compass
4. Join third point to C ( say KC)
5. Through the fourth point , draw a line parallel to KC meeting CBC extended at C'
6. Through C'draw C'A'parallel to AC.
I hope you understood the method
If numerator of the ratio is larger the point is an external point.
Answered by | 9th Oct, 2008, 08:55: PM
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