I have a question in construction??

Asked by  | 9th Oct, 2008, 08:22: PM

Expert Answer:

 

 

1.Draw the triangle ABC

2.Draw aray BX making an acute angle with BC on the other side of the triangle.

3.Locate 4 points on the arm BX (the larger out of 4 and 3) , with your compass

4. Join third point to C ( say KC)

5. Through the fourth point , draw a line parallel  to KC meeting CBC extended at C'

6. Through C'draw C'A'parallel to AC.

I hope you understood the method

If numerator of the ratio is larger the point is an external point.

 

Answered by  | 9th Oct, 2008, 08:55: PM

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