I cannot approach the question written below
Asked by | 16th May, 2008, 10:14: AM
Let the speed of motorboat in still water be x km/h
Let the speed of water be y km/h
Speed downstream is (x+y) km/h
Speed upstream is (x-y) km/h
Raft covers 11 km in 11/y hour as its speed is y km/h
After moving in the forward direction for 60 minutes, the boat turns back.
Distance covered by motorboat in forward direction in 60 mins or 1 h is (x+y)(1)
time the motoboat moves in the reverse direction is (11/y-1)
This distance will be (x-y)(11/y-1)
The difference between these distances is 11km.
Write the equation and then solve it.
Answered by | 20th May, 2008, 02:53: PM
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