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CBSE Class 12-science Answered

I am trying it but not arriving at any of the given option... help me to solve it...
 
Asked by nitishkrnehu09 | 23 Nov, 2017, 10:06: AM
answered-by-expert Expert Answer
 
In one model of the electron, the electron of mass me is thought to be a uniformly charged shell of radius R and total charge e, whose electrostatic energy E is equivalent to its mass me via Einstein's mass energy relation E=mec2. In the this model, R is approximately
 
T. E equals fraction numerator 1 over denominator 8 space pi space epsilon end fraction x q squared over R space space space  m c squared equals fraction numerator 1 over denominator 2 x 4 space pi space epsilon end fraction x q squared over R space space space  9.1 x 10 to the power of negative 31 end exponent x left parenthesis 3 x 10 to the power of 8 right parenthesis squared equals 9 x 10 to the power of 9 x fraction numerator 1.6 x 10 to the power of negative 19 end exponent over denominator 2 x R end fraction  R equals fraction numerator 9 x 10 to the power of 9 x left parenthesis 1.6 x 10 to the power of negative 19 end exponent right parenthesis squared over denominator 9.1 x 10 to the power of negative 31 end exponent x left parenthesis 3 x 10 to the power of 8 right parenthesis squared end fraction equals fraction numerator 23.04 x 10 to the power of negative 29 end exponent over denominator 81.9 x 10 to the power of negative 15 end exponent end fraction equals 1.4 x 10 to the power of negative 15 end exponent space m
Answered by Gajendra | 23 Nov, 2017, 01:01: PM

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CBSE 12-science - h
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Asked by h | 29 Mar, 2024, 02:17: AM
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