I am totally confused that what values for object and image distance should I take while solving the numericals involving the task of finding the corrective focal length of a myopic and hypermetropic eye????

Asked by  | 1st Mar, 2012, 10:24: AM

Expert Answer:

A person affected by hypermetropia has a shorter-than-normal eye ball, making the
retina too close to the lens system. This causes images of near objects to be formed
behind the retina.
For Myopic :
concave lens is used to correct it and value of u is to reduce the focal length of concave lens from original object distance.
v = focal length of concave lens.
For hypermetropia:
For the object distance, increase the distance of object by focal length of convex lens
and final image distance will be focal length of the convex lens

Answered by  | 1st Mar, 2012, 12:00: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.