CBSE Class 10 Answered
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Asked by khushal305 | 05 Jun, 2009, 05:28: PM
Expert Answer
1288=[575*2]+138
575=[138*4]+23
138=23*6+0
The step at which the remainder is zero has 23 as the divisor, so the HCF is 23.
Now reverse the steps.
23= 575-[138*4]=575-[1288-(575*2)]*4=575(9)+1288(-4)
Thus we have expressed the remainder 23 in terms of 1288 and 575.
Theother question also can be done by the same method.
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Answered by | 09 Jun, 2009, 04:32: PM
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