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CBSE Class 12-science Answered

How will the energy stored and the electric field inside the capacitor be affected when it is completely filled with dielectric of dielectric constant k
Asked by bijuaylara111 | 25 Jul, 2017, 07:10: PM
answered-by-expert Expert Answer
1) The electric field between two charged plates of a capacitor is given by the relation E = Q/Aε0.
 
2) With the introduction of a dielectric, the field now becomes E = Q/A(Kε0). Hence, the field decreases and becomes K times by the introduction of a dielectric.
 
3) The energy stored in a capacitor is U = Q2/2C. After the introduction of dielectric capacitance becomes C' = KC. So, the energy stored becomes U' = Q2/2C' = Q2/2KC. Therefore, the energy decreases and becomes 1/K times the original.
Answered by Romal Bhansali | 26 Jul, 2017, 11:52: AM

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