CBSE Class 12-science Answered
how to write iupac name of K4[Mn(CN)6]
Asked by lakshmiprasadsingh | 12 Feb, 2014, 11:38: AM
Expert Answer
- K4 [ Mn(CN)6 ] is a coordination compound.
- The potassium ion is the cation and the complex ion is the anion.
- As there are 4 K+ binding with a complex ion, the charge on the complex ion must be - 4.
- As each ligand carries –1 charge, the oxidation number of Mn must be +2.
- What is written in the [ ] is known as the coordination complex.eg [ Mn (CN)6 ]
- The coordination complexes are made of a central metal ,[Mn] +(Ligands)] ;(CN) in this case.
- Ligands are simple atoms or groups of atoms that donate electrons.
- What is written outside[ ] , in this case K4, is the primary valency / ionisable valency of the metal atom[within the complex].
- Central metal is Mn here. Let the oxidation state of Mn ,the central metal be x
K4 [ Mn(CN)6 ]
(+4) + x (-6) = 0
- Thus x , the Oxidation state of the central metal atom Mn is II which written at the end of the name.
- The name of central metal should end with “ate”. Here “manganate (II)”
- The ligands should be given prefix as hexa as there are 6 ligands.
- Hence the IUPAC name is potassium hexacyanomanganate(II)
Answered by | 12 Feb, 2014, 12:10: PM
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