How to solve this...
 

Asked by nitishkrnehu09 | 23rd Nov, 2017, 09:33: AM

Expert Answer:

begin mathsize 16px style ex squared plus πy squared minus 2 straight e squared straight x minus 2 straight pi squared straight y plus straight e cubed plus straight pi cubed equals πe
straight e open parentheses straight x squared minus 2ex plus straight e squared close parentheses plus straight pi open parentheses straight y squared minus 2 πy plus straight pi squared close parentheses equals πe
straight e open parentheses straight x minus straight e close parentheses squared plus straight pi open parentheses straight y minus straight pi close parentheses squared equals πe
open parentheses straight x minus straight e close parentheses squared over straight pi plus open parentheses straight y minus straight pi close parentheses squared over straight e equals 1
Here comma space straight a equals square root of straight pi space and space straight b equals square root of straight e
Now space find space PS subscript 1 plus PS subscript 2 space equals 2 straight a
you space will space get space 2 square root of straight pi. end style

Answered by Sneha shidid | 29th Nov, 2017, 11:04: AM