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CBSE Class 10 Answered

how to solve this problem .... i want a clear explaination ... please.  
 
SOLVE :-  x=____1_____ , (x is no equal to 2 )
                2- ___1____
                  2- __1__
                        2-x
 
 
 
Asked by Shubham singh | 23 Nov, 2014, 10:01: AM
answered-by-expert Expert Answer
G i v e n space e q u a t i o n space i s x equals fraction numerator 1 over denominator 2 minus begin display style fraction numerator 1 over denominator 2 minus begin display style fraction numerator 1 over denominator 2 minus x end fraction end style end fraction end style end fraction R e w r i t i n g space t h e space a b o v e space e q u a t i o n comma space w e space h a v e comma open square brackets 2 minus fraction numerator 1 over denominator 2 minus begin display style fraction numerator 1 over denominator 2 minus x end fraction end style end fraction close square brackets cross times x equals 1 rightwards double arrow open square brackets 2 minus fraction numerator 1 over denominator begin display style fraction numerator 2 cross times open parentheses 2 minus x close parentheses minus 1 over denominator 2 minus x end fraction end style end fraction close square brackets cross times x equals 1 rightwards double arrow open square brackets 2 minus fraction numerator 1 over denominator begin display style fraction numerator open parentheses 4 minus 2 x close parentheses minus 1 over denominator 2 minus x end fraction end style end fraction close square brackets cross times x equals 1 rightwards double arrow open square brackets 2 minus fraction numerator 2 minus x over denominator begin display style 4 minus 2 x minus 1 end style end fraction close square brackets cross times x equals 1 rightwards double arrow open square brackets 2 minus fraction numerator 2 minus x over denominator begin display style 3 minus 2 x end style end fraction close square brackets cross times x equals 1 rightwards double arrow open square brackets fraction numerator 2 open parentheses 3 minus 2 x close parentheses minus 2 plus x over denominator begin display style 3 minus 2 x end style end fraction close square brackets cross times x equals 1 rightwards double arrow open square brackets 6 minus 4 x minus 2 plus x close square brackets cross times x equals 3 minus 2 x rightwards double arrow open square brackets 4 minus 3 x close square brackets cross times x equals 3 minus 2 x rightwards double arrow 4 x minus 3 x squared equals 3 minus 2 x rightwards double arrow 3 x squared minus 4 x plus 3 minus 2 x equals 0 rightwards double arrow 3 x squared minus 6 x plus 3 equals 0 rightwards double arrow x squared minus 2 x plus 1 equals 0 rightwards double arrow open parentheses x minus 1 close parentheses squared equals 0 rightwards double arrow x equals 1 comma 1
Answered by Vimala Ramamurthy | 23 Nov, 2014, 01:35: PM
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