how to solve -64a3-2a+48a2

Asked by devanandanair12345 | 22nd May, 2019, 07:34: PM

Expert Answer:

 The question should be
1-64a3-12a+48a2
= (1) - (4a)3 - 3(1)2 (4a) + 3(1)(4a)2
= (1 - 4a)3    ... since (a - b)3 = a3 - b3 - 3a2b + 3ab2  
= (1 - 4a)(1 - 4a)(1 - 4a)

Answered by Yasmeen Khan | 23rd May, 2019, 10:18: AM