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how to solve 2nd part
Asked by lakshyasaxena970 | 07 Jul, 2021, 10:42: PM
Expert Answer
Part (a)
As shown in figure , Train-B has to travel a distance 500 m to overtake Train-A .
Relative velocity of Train-B with respect to train-A is (40-20) = 20 m/s .
Hence time taken to travel 500 m distance = distance / relative velocity = 500 / 20 = 25 s
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Part (b)
Required acceleration a for train-B to overtake train-A in a time duration of t seconds is determined
from the following equation of motion
S = [ uB - uA ] t + (1/2) a t2
Where S is distance to be travelled, uA is the initial speed of train-A and uB is initial speed of train-B
Since both train are moving with same speed , [ uB - uA ] = 0
Hence , we have , S = (1/2) a t2 or a = ( 2 S ) / t2
acceleration a = ( 2 × 500 ) / (50 × 50 ) = 0.4 m/s2
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