how to solve    1/√7-√6
solve with defination

Asked by rehanahmadxlx | 31st May, 2016, 10:23: PM

Expert Answer:

begin mathsize 12px style fraction numerator 1 over denominator square root of 7 minus square root of 6 end fraction
T o space r a t i o n a l i s e space t h e space d e n o m i n a t o r comma space w e space m u l t i p l y space b o t h space n u m e r a t o r space a n d space t h e space d e n o m i n a t o r
b y space square root of 7 plus square root of 6

fraction numerator 1 over denominator square root of 7 minus square root of 6 end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator open parentheses square root of 7 minus square root of 6 close parentheses open parentheses square root of 7 plus square root of 6 close parentheses end fraction
equals fraction numerator square root of 7 plus square root of 6 over denominator open parentheses square root of 7 close parentheses squared minus open parentheses square root of 6 close parentheses squared end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator 7 minus 6 end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator 1 end fraction
equals square root of 7 plus square root of 6 end style

Answered by satyajit samal | 1st Jun, 2016, 11:24: AM