how to find work done to move a charge attracted by another charge from its original place to a another place 2 metres away.

Asked by asthahunny | 20th Jun, 2015, 03:51: PM

Expert Answer:

Let e be the charge attracted by another charge from its original place to a another place 2 m away.
Let P be point at which charge is located.
Potential at a point P due to charge e is given as,
begin mathsize 12px style straight V equals fraction numerator 1 over denominator 4 πε subscript 0 end fraction times straight q over straight r equals 9 cross times 10 to the power of 9 cross times straight e over 2 equals 4.5 straight e cross times 10 to the power of 9 space straight V From space the space defination comma space potential space at space straight a space point space straight P space equals space the space work space done space in space bringing space charge space from space its space original space place space to space straight a space another space place space at space straight a space point space straight P. Therefore comma space work space done space is space given space as comma straight W equals charge cross times Potential space at space point space straight P straight W equals charge cross times 4.5 straight e cross times 10 to the power of 9 space end style
 
Note: By substituting value of charge you will get the value of work done.

Answered by Priyanka Kumbhar | 22nd Jun, 2015, 09:20: AM

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