How to find the oxidation state of Cobalt and chromium in [Co(NH3)6][Cr(CN)6]?
Asked by rayyan20151 | 9th Jan, 2020, 11:40: AM
In complex [Co(NH3)6][Cr(CN)6], [Co(NH3)6] is a cationic part and [Cr(CN)6] is anionic part.
[Co(NH3)6] - NH3 is neutral ligand and
[Cr(CN)6] - CN ligand is with -1 charge
let oxidation state of Co be 'x'
x + 0 = 3
x = +3
let oxidation state of Cr be 'x'
x-6 = -3
x = +3
Answered by Varsha | 9th Jan, 2020, 02:44: PM
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