How to find the oxidation state of Cobalt and chromium in  [Co(NH3)6][Cr(CN)6]?

Asked by rayyan20151 | 9th Jan, 2020, 11:40: AM

Expert Answer:

In complex [Co(NH3)6][Cr(CN)6], [Co(NH3)6] is a cationic part and  [Cr(CN)6] is anionic part.
 
 [Co(NH3)6] - NH3 is neutral ligand and 
 
   [Cr(CN)6] - CN ligand is with -1 charge
So, 
[Co(NH3)6]3+ 
let oxidation state of Co be 'x'
 
x + 0 = 3
 
x = +3
 
For 
[Cr(CN)6
let oxidation state of Cr be 'x'
x-6 = -3
 
x = +3

Answered by Varsha | 9th Jan, 2020, 02:44: PM