how to find the maximum and minimum oxidation no. of a radical or an atom. i remember that a formula was their in this context related to mendeleev's periodic table.kindly help.

Asked by architsrivastava02 | 14th Jul, 2011, 04:21: PM

Expert Answer:

 

 The algebraic sum of all the oxidation no. of elements in a radical is equal to the net charge on the radial. Oxidation number can be zero, +ve, –ve (integer or fraction) .

 Maximum oxidation no. of an element is = Group no (Except O and F)

Minimum oxidation no. of an element is = Group no. –8 (Except metals)

For metals the oxidation number is always positive.

For Alkali metals (i.e., I A group — Li, Na, K, Rb, Cs, Fr) it is always +1 and for Alkaline earth metals (i.e., II A group—Be, Mg, Ca, Sr, Ba, Ra) it is always +2.

Answered by  | 14th Jul, 2011, 11:53: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.