how to find the maximum and minimum oxidation no. of a radical or an atom. i remember that a formula was their in this context related to mendeleev's periodic table.kindly help.
Asked by architsrivastava02
| 14th Jul, 2011,
04:21: PM
Expert Answer:
The algebraic sum of all the oxidation no. of elements in a radical is equal to the net charge on the radial. Oxidation number can be zero, +ve, ve (integer or fraction) .
Maximum oxidation no. of an element is = Group no (Except O and F)
Minimum oxidation no. of an element is = Group no. 8 (Except metals)
For metals the oxidation number is always positive.
For Alkali metals (i.e., I A group Li, Na, K, Rb, Cs, Fr) it is always +1 and for Alkaline earth metals (i.e., II A groupBe, Mg, Ca, Sr, Ba, Ra) it is always +2.
The algebraic sum of all the oxidation no. of elements in a radical is equal to the net charge on the radial. Oxidation number can be zero, +ve, ve (integer or fraction) .
Maximum oxidation no. of an element is = Group no (Except O and F)
Minimum oxidation no. of an element is = Group no. 8 (Except metals)
For metals the oxidation number is always positive.
For Alkali metals (i.e., I A group Li, Na, K, Rb, Cs, Fr) it is always +1 and for Alkaline earth metals (i.e., II A groupBe, Mg, Ca, Sr, Ba, Ra) it is always +2.
Answered by
| 14th Jul, 2011,
11:53: AM
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