How to find co ordination no. and oxidation state of central atom in a coordinate compound??

Asked by Rishabh Tripathi | 18th Jun, 2013, 11:02: PM

Expert Answer:

eg 1 -
K4     [ Fe (CN)6 ]
what is written in the [ ]  is known as the coordination complex.eg [ Fe (CN)6 ]
the coordination complexs are made of a central metal ,[Fe] +(Ligands)] ;(CN) in this case.
Ligands are simple atoms or groups of atoms that donate electrons.
 
what is written outside[ ] , in this case K4, is the primary valency / ionisable valency of the metal atom[within the complex].
Central metal is Fe here.let the  Oxidation state of Fe ,the central metal be  x 
K4     [ Fe  (CN)6 ]
(+4)  + x   (-6)  = 0  
thus x , the Oxidation state of the central metal atom Fe  is II 
 
eg 2 -
K3     [ Fe (CN)6 ]
what is written in the [ ]  is known as the coordination complex. [ Fe (CN)6 ] again
 
what is written outside[ ] , in this case K4, is the primary valency / ionisable valency of Fe, the
Central metal
.let the  Oxidation state of Fe  be y
K3     [ Fe  (CN)6 ]
(+3)  + x   (-6)  = 0  
thus x , the Oxidation state of the central metal atom Fe  is III 
 

Answered by  | 19th Jun, 2013, 01:18: PM

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