how to determine no. of valence electrons by lewis structure in a cyanide ion
Asked by rajawatnakul3 | 12th Sep, 2015, 11:10: AM
Below given is the Lewis structure for the cyanide ion:
From the above structure,
1. There are 6 paired electrons, 4 unpaired electrons and two electrons from the negative charge.
2. Hence, total electrons involved are 6+4+2= 12 electrons.
3. Total valence electrons= total electrons involved - electrons of negative charge = 12-2=10 electrons.
4. Thus, the total valence electrons in cyanide ion = 10 electrons.
Answered by Prachi Sawant | 12th Sep, 2015, 06:24: PM
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