CBSE Class 11-science Answered
how to derive the value of gas constant R.
Asked by NAKSHATRA | 20 Sep, 2013, 11:14: AM
Expert Answer
At STP, 1 mole of gas will occupy 22.4 L.
Use those conditions with PV = nRT to determine R.
P = 101,325 Pa
V = 22.4 L
n = 1 mol
T = 273 K
R = PV/nT
R = (101,325 Pa) (22.4 L)/(1 mol)(273 K)
R = 8314 L Pa/K mol
Use those conditions with PV = nRT to determine R.
P = 101,325 Pa
V = 22.4 L
n = 1 mol
T = 273 K
R = PV/nT
R = (101,325 Pa) (22.4 L)/(1 mol)(273 K)
R = 8314 L Pa/K mol
Answered by | 22 Sep, 2013, 08:58: AM
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