CBSE Class 9 Answered
how to construct a triangle when perimeter is given
Asked by | 08 Mar, 2013, 09:43: PM
Expert Answer
Given : In ΔABC, AB+BC+CA = 10.5 cm, angleB = 70° & angleC = 90°.
Required : To construct the ΔABC.
Steps of Construction:
- Draw DE = 10.5 cm.
- At D, construct angleEDP = 1/2 of 70° = 35° and at E, construct angleDEQ = 1/2 of 90° = 45o.
- Let DP and EQ meet at A.
- Draw perpendicular bisector of AD to meet DE at B.
- Draw perpendicular bisector of AE to meet DE at C.
Answered by | 09 Mar, 2013, 09:46: PM
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