how to construct a triangle when perimeter is given

Asked by  | 8th Mar, 2013, 09:43: PM

Expert Answer:

Given          : In ΔABC, AB+BC+CA = 10.5 cm, angleB = 70° & angleC = 90°.

          Required      : To construct the ΔABC.

          Steps of Construction:

  1. Draw DE = 10.5 cm.
  2. At D, construct angleEDP = 1/2 of 70° = 35° and at E, construct angleDEQ = 1/2 of 90° = 45o.
  3. Let DP and EQ meet at A.
  4. Draw perpendicular bisector of AD to meet DE at B.
  5. Draw perpendicular bisector of AE to meet DE at C.
          Join AB and AC. Then, ABC is the required triangle.

Answered by  | 9th Mar, 2013, 09:46: PM

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