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CBSE Class 9 Answered

how to construct a triangle when perimeter is given
Asked by | 08 Mar, 2013, 09:43: PM
answered-by-expert Expert Answer

Given          : In ΔABC, AB+BC+CA = 10.5 cm, angleB = 70° & angleC = 90°.

          Required      : To construct the ΔABC.

          Steps of Construction:

  1. Draw DE = 10.5 cm.
  2. At D, construct angleEDP = 1/2 of 70° = 35° and at E, construct angleDEQ = 1/2 of 90° = 45o.
  3. Let DP and EQ meet at A.
  4. Draw perpendicular bisector of AD to meet DE at B.
  5. Draw perpendicular bisector of AE to meet DE at C.
          Join AB and AC. Then, ABC is the required triangle.
Answered by | 09 Mar, 2013, 09:46: PM

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