How to calculate oxidation number of PbSO4??

Asked by  | 25th Mar, 2009, 06:54: PM

Expert Answer:

Let the oxidation number of Pb=x

Oxidation number of S=+6

Oxidation number of O=-2

Sum of all oxidation number =0

Therefore x+6-8=0

Therefore oxidation number of Pb is +2

Answered by  | 26th Mar, 2009, 10:23: AM

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