How much work has to be done to maintain electric dipole with moment 6 x 10-8 cm and angle 60in an electric field of magnitude 1.2 x 104 N/C?

Asked by Topperlearning User | 24th Apr, 2015, 01:59: PM

Expert Answer:

Given:

P = 6 x 10-8 cm

E = 1.2 x 104 N/C

θ = 60o

Work done = potential energy of dipole 

= pE (cos 60o)

= -6 x 10-8 x 1.2 x 104  x 0.5

W = 3.6 x 10-4 J

Answered by  | 24th Apr, 2015, 03:59: PM