How much pure alcohol be added to 400 ml of a 15 percent solution to make its strength 32 percent

Asked by ajayrath7 | 3rd Dec, 2017, 07:22: AM

Expert Answer:

begin mathsize 16px style Quantity space of space alcohol space in space 400 space ml space solution equals 15 over 100 cross times 400 equals 60 space ml
Let space straight x space ml space of space alcohol space be space added.
Then comma space we space have
fraction numerator 60 plus straight x over denominator 400 plus straight x end fraction equals 32 over 100
rightwards double arrow 6000 plus 100 straight x equals 12800 plus 32 straight x
rightwards double arrow 68 straight x equals 6800
rightwards double arrow straight x equals 100 space ml end style

Answered by Rashmi Khot | 3rd Dec, 2017, 01:11: PM