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CBSE Class 12-science Answered

how much of cane sugar should be dissolved in 0.300Kg so that resulting solution has same boiling point as that of 3gm of Urea in 0.1Kg of Water
Asked by Hritwik mishra | 19 Aug, 2011, 07:13: PM
answered-by-expert Expert Answer

 

The elevation in boiling point for sugar solution is,

                                  ?Tb(sucrose) = (Kb X Wsucrose) / (Msucrose X Wwater )

 

Where, Msucrose = 342 gm/mole

             Wwater = 0.300 kg

 

Similarly, the elevation in boiling point for urea solution is,

                    ?Tb(urea) = (Kb X Wurea ) / (Murea X Wwater )

Where, Murea = 60 gm/mole

             Wwater = 0.1 kg

According to the question, ?Tb(sucrose) = ?Tb(urea)

        

     (Kb X Wsucrose) / (Msucrose X Wwater ) = (Kb X Wurea ) / (Murea X Wwater )

 

Or, Wsucrose / (342 X 0.300 ) = 3  / ( 60 X 0.1 )

  

Wsucrose  = 51.33 gm

Answered by | 23 Aug, 2011, 04:02: PM
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