How much maximum amount of Alumininum metal is deposited at cathode by passing one ampere current for 96500seconds through molten AlCl3?

Asked by sourabh7jain | 7th Jun, 2016, 11:41: AM

Expert Answer:

Given:
c = 1 ampere
t = 96500 seconds
 
To find: Weight of Al deposited = ?
begin mathsize 12px style Solution colon straight e space equals space fraction numerator 27 over denominator 3 space cross times space 96500 end fraction Weight space of space Al space deposited space equals space equals space fraction numerator 27 space cross times space 1 space cross times space 96500 over denominator 3 space cross times space 96500 end fraction space equals space 9 space gm end style
 

Answered by Hanisha Vyas | 9th Jun, 2016, 12:04: PM