how much energy is transformed when 10A current flows through a resister of 5 ohm for 30 minutes?

Asked by satyam kumar | 18th Aug, 2012, 05:33: PM

Expert Answer:

power transfrred in that resister: P = I2R = 500 W
 
thus energy transformed = P x t = 500 x 30 x 60 = 900000 J

Answered by  | 19th Aug, 2012, 11:11: AM

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