how many values?

Asked by geethika | 24th Oct, 2010, 11:56: AM

Expert Answer:

Dear Student,
 
sin3x = sinx
 
=> 3sinx - 4sin3x = sinx
 
=> 2sinx - 4sin3x = 0
 
=> 2sinx (1 - 2sin2x) = 0
 
Therefore the possible solutions for this equation are
 
sinx = 0 => x = pi, -pi, 0
 
and
 
sin2x = 1/2
 
 
 
Hence, the number of possible solutions are 7.
 
 
Regards Topperlearning.

Answered by  | 25th Oct, 2010, 05:32: PM

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