CBSE Class 11-science Answered
how many values?
Asked by geethika | 24 Oct, 2010, 11:56: AM
Expert Answer
Dear Student,
sin3x = sinx
=> 3sinx - 4sin3x = sinx
=> 2sinx - 4sin3x = 0
=> 2sinx (1 - 2sin2x) = 0
Therefore the possible solutions for this equation are
sinx = 0 => x = pi, -pi, 0
and
sin2x = 1/2
Hence, the number of possible solutions are 7.
Regards Topperlearning.
Answered by | 25 Oct, 2010, 05:32: PM
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