How many numbers of four digit greater than 2300 can be formed with digits 0, 1, 2, 3, 4, 5and 6 no digit being repeated in any number ?
Asked by Ashu Jain | 26th Oct, 2013, 12:22: AM
Given that the number should be greater than 2300 and the number of digits is four.
Therefore, the numbers with 3,4,5,6 in thousands place will be greater than 2.
But if the number in thousands place is 2, then there is a restriction in hundreds place to make the number greater than 2.
Let us consider two cases.
When 2 occurs at thousands place:
The thousands place can be filled up by 2 in 1 way
The hundreds place can be filled up by any of the numbers 3,4,5,6 in 4 ways.
So the remaining two places can be filledup in ways.
Therefore the total numbers formed inthis case = 1 x 4 x = 80
When 3,4,5, or 6 occurs at thousands place.
The thousands place can be filled in 4 different ways
So the remaining three places can be filledup in 6P3 ways.
Therefore the total numbers formed inthis case = 4 x 6P3 = 480
Therefore, the required number = 80 +480 = 560
Answered by Vimala Ramamurthy | 26th Oct, 2013, 07:53: AM
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