how many grams of oxygen gas contain the same number of molecules as are present in 16g of sulphur dioxide (atomic masses=sulphur 32 oxygen 16

Asked by  | 21st Nov, 2013, 06:13: PM

Expert Answer:

Solution:

Mass of sulphur dioxide = 64 g

So 1 mole = 64 g of sulphur dioxide

Therefore 16 g of sulphur dioxide = 1 × 16 = 1/ 4 mole

                                                    64

Now, 1 mole of oxygen = 32 g

So 1/4 mole of oxygen = 32   × 1/4 = 8 g

So 8 g of oxygen will contain the same number of molecules as 16 g of sulphur dioxide.

Answered by Vaibhav Chavan | 22nd Nov, 2013, 09:21: AM

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