How many gms of ferric sulphide will contain total number of atoms equal to avogadros number

Asked by Saurabh Budholiya | 7th Apr, 2011, 11:11: PM

Expert Answer:

Molecular weight 87.91 g/mol
So, 87.91 g of FeS will contain 6.022 X 1023  molecules of FeS.
As, one molecule of FeS has one atom of Fe and one atom of S, 87.91 g FeS will have  6.022 X 1023  atoms of Fe and  6.022 X 1023  atoms of S. But half amount of FeS will contain total atoms = Avagadro's number
But, 87.91/2 g of FeS will contain total atoms = 6.022 X 1023  .
So, 43.95 g of FeS will contain 6.022 X 1023 atoms total.

Answered by  | 8th Apr, 2011, 12:41: PM

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