CBSE Class 9 Answered
How many aluminum ions are present in 0.51 grams of Aluminum Oxide?
Asked by | 03 Jan, 2013, 05:23: PM
Expert Answer
Write the chemical formula : Al2O3
Calculate the number of moles for aluminum oxide.
Calculate the number of moles for aluminum oxide.
You should know the formula which is the mass given (0.51g) divided by the Mass of aluminum oxide. Mass of 1 mole Al2O3 = 102 g.
So, n = 0.51 /102 g = 0.005 = 5 x 10-3
Since there is '2' moles of Aluminium per mole of Al2O3 you multiplly the number of moles calculated for aluminum oxide by 2.
Since there is '2' moles of Aluminium per mole of Al2O3 you multiplly the number of moles calculated for aluminum oxide by 2.
Number of Al2O3 molecules in 5 x 10-3 mole = (6.032 x 1023)x( 5 x 10-3) = 30.115 x 1020
Number of aluminum ions per molecule = 2.
Number of aluminum ions in mole Al2O3 =30.115 x 1020 x 2 = 60.23 x 1020
Answered by | 05 Jan, 2013, 04:55: PM
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