How many 1's are there between 1 and 1000?Can u please explain the method of doing this question?

Asked by  | 25th Nov, 2012, 10:53: PM

Expert Answer:

Total number of arrangement of digit in 3 places =10*10*10=1000
total number of digits involved=1000*3=3000
and all the digits are equally likely therfor each one will occur 3000/10=300 times
Therfor number of 1's occuring =300

Answered by  | 1st Dec, 2012, 12:23: AM

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