How many 176 ? resistors (in SERIES) are required to carry 5 A on a 220 V line?

Asked by  | 26th Sep, 2012, 05:06: PM

Expert Answer:

in parallel, the total equivalent of resistors will be calculated as:
R = 176/n ohm
where as in series it would be R = 176n ohm
thus the number of resistors would be:
(by ohms law)
220 = 5 (176n)
n = 220/(176)(5) <1
thus it is not possible to carry 5 A by this line using resistors in series.

Answered by  | 27th Sep, 2012, 09:03: AM

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