CBSE Class 10 Answered
How many 176 ohm resistors ( in parallel) are required to carry 5A on a 220V line?
Asked by adalroshan2464 | 28 Mar, 2019, 02:37: PM
Expert Answer
let us assume there is n number of resistor required. since all the resistors are connected in parallel connection so the equivalence resistance = R = 176/n Ω
Using ohms law
V =IR
220 = 5×(176/n)
n = (176×5)/220
n = 880/220 = 4
So the number of resistor would be 4
Answered by Ankit K | 28 Mar, 2019, 03:05: PM
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